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Q: In general describe the rectangle that has the least area for a fixed perimeter?

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The greatest area for a fixed perimeter will be when all the sides are equal or when the rectangle approaches the shape of a square.

The maximum area for a rectangle of fixed perimeter is that of the square that can be formed with the given perimeter. 136/4 = 34, so that the side of such a square will be 34 and its area 342 = 1156.

fixed perimeter is the perimeter being fixed

nope because if u have a square with a side length of 4 then the perimeter is 16 and the area is 16 and say if u have a rectangle with side lengths of 2 and 6 then the perimeter is 16 but the area is 12 so the answer is no

P (perimeter of a rectangle) = 2*l+2*w 2*24+2*w > 100 2*w > 52 w > 26 Any width greater than 26cm will cause the perimeter to be greater than 100cm.

A perimeter that will not change.

The clever person might realize that, though an infinite number of rectangles can be created with a fixed perimeter, there is a maximum and minimum area that any rectangle formed under the constriction can have. And we can work with that. The minimum area will be "near" zero. (With an area "at" zero, the rectangle will collapse and/or disappear.) The rectangle with "maximumized" area for a fixed perimeter will be a square. Its side (designated by "s") will be one fourth of the perimeter (designated by "p"). If s = p/4 and we use the formula for finding the area (As) of a square substituing our "p/4" for the side length "s" we will get the equation: As = (p/4)2 Our rectangle(s) will all have an area (Ar) within this range: Zero is less than Ar which is less than or equal to (p/4)2 Though we couldn't come up with a precise answer, we came up with the next best thing with the information supplied.

For a fixed area, the perimeter is minimum for a circle, but has no maximum. Fractal figures (such as Koch snowflake) may have a finite area within an infinite perimeter.

L + W = P/2 = 49 so Length must be greater than 35 cm

Anything greater than 24 cm. P = 2*L + 2*W, since the length is fixed at 24cm we have: 2*(24cm) +2*W > 96cm 2W > 96 - 48cm 2W > 48cm, or Width > 24cm. So any width greater than 24cm will make the perimeter >96cm. Obviously a width of 24cm wouldn't work since a polygon with all four sides equal would be a square and not a rectangle.

No

Conventionally, length > width. With that assumption, if L is the length and W the width (both in metres) then 3.75 < L < 7.5 and W = 7.5 - L If L = 3.75 then W = L and the rectangle becomes a square.

A fixed area of a rectangle is an area that doesn't change. An area is a quantity that measures the space of a shape.Consider this example:A = length x width, which is the formula of a rectangleIf A is fixed, then it depends on what values length and width are. Then, length is indirectly proportional to width in order for A to remain fixed.

Area rectangle = length x width (using same units).

The perimeter is the sum of all of the sides of the figure. So, simply add up ALL the sides to discover what the perimeter is.

Colorado is a perfect rectangle.

I don't know what you mean by fixed area. All I know is that the area of a rectangle is the length times the width. As long as you don't change the length or the width, or change it into a different kind of shape, this area will remain fixed.

This law is: a chemical compound has the components in a fixed ratio.This law don't has today a general validity.

The rectangle with the most area for a given perimeter is the square.Build the room square, with sides of 94-ft. The area is 8,836 square ft.

Approximately 6,789.98 units2

It depends on the shape of the acre, it is not a fixed distance.

You can't: there are many different shapes with the same area that have different perimeters. For example, if you have an area of 100, the figure could be a 10 by 10 square (with a perimeter of 40), a 20 by 5 rectangle (with a perimeter of 50), or even a circle with a radius of about 5.64, and a perimeter of about 35.44. You might be able to figure out the perimeter if you know something about the shape. If you know it's a square, for example, then the perimiter is 4 times the square root of the area. It's also interesting to note that of all shapes with the same area, the one with the smallest perimeter will be a circle. This is why soap bubbles are round: their contents are fixed, but surface tension makes the bubble "try" to minimize the perimeter.

The perimeter of a rectangle is 2 x length + 2 x width. If the width is 16 then 78 = 2 x length + 2 x 16 2 x length = 78 - 32 = 46 length = 23. For the perimeter to be greater than 78 cm, the length must be greater than 23 cm

no If the shape of the object is not fixed, it would be possible to alter the shape of the perimeter, but not the length, i.e., the distance around the object being enclosed.